Before I go to that, let me say I've now entered over 2,000 bills worth over $8,000.
While entering bills, I got to wondering what the odds are of getting your 7-digit telephone number in order and sequentially within the 8-digit serial number.
I think I can do part of it. For the first seven numbers OR the last seven numbers to match, the odds are 1 in 8 million. The first number cannot be a one or zero, so that leaves eight possibilities; the next six could conceivably be any one of ten possibilities. I guess the likelihood of someone's phone number being 600-0000 are slim to none, but I have no way of knowing what combinations are not allowed.
My question is what is the liklihood of EITHER the first seven or last seven being your own phone number? This is where my college education is either lacking or forgotten. The first number could either be one of ten if the phone number is the last seven numbers, or one of eight if the phone number is the first seven. In any event, I would think that the odds would be less than 1 in 8M since you now have two chances of matching per bill instead of the previous one.
Anyone dare working this out?